Find the Cube Using Identity (i) $105$ (ii) $27$ (iii) $45$

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Solution

$i) 105^{3} = 105 \times 105 \times 105 = 11, 57, 625$
$i i) 27^{3} = 27 \times 27 \times 27 = 19, 683$
$i) 45^{3} = 45 \times 45 \times 45 = 91, 125$

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Similar questions

Evaluate these using identity:

(i) 55 × 45; (ii) 33 × 27; (iii) 8.5 × 9.5; (iv) 102 × 98.

99^{3}

1001^{2}

105^{3}

105 \times 108

91 \times 106

107^{3}

Using the identities of algebraic expressions, Find :

$(i) 102^{2}$

$(i i) 53^{2}$

$(i i i) 1001^{2}$ [3 MARKS]

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