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Question

Find the cubes of:

(1) (1)3

(2) (−2)3

(3) (3)3

(4) (4)3

(5) (−5)3

(6) (23)3

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Solution

(1) (1)3 = 1 × 1 × 1 = 1

(2) (−2)3 = (−2) × (−2) × (−2) = −8

(3) (3)3 = 3 × 3 × 3 = 27

(4) (4)3 = 4 × 4 × 4 = 64

(5) (−5)3 = (−5) × (−5) ×(−5) = −125

(6) (23)3 = 23 × 23 × 23 = 8 × 8 × 8 = 512


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