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Cube Numbers

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Question

Find the cubes of :
(i) -11 (ii) -12 (iii) -21

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Solution

$(i) (- 11)^{3} = - (11)^{3} = - (11 \times 11 \times 11) = - 1331 (i i) (- 12)^{3} = - (12)^{3} = - (12 \times 12 \times 12) = - 1728 (i i i) (- 21)^{3} = - (21)^{3} = - (21 \times 221 \times 21) = - 9261$

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