Find the cubes of :
(i) 2.1
(ii) 0.4

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Solution

(i) (2.1)³ = $\frac{(21 \times 21 \times 21)}{(10 \times 10 \times 10)} = \frac{9261}{1000} = 9.261$
(ii) (0.4)³ = $\frac{4 \times 4 \times 4}{10 \times 10 \times 10} = \frac{64}{1000} = 0.064$

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Similar questions

Find the cubes of:

(i) 2.1 (ii) 0.4 (iii) 1.6

(iv) 2.5 (v) 0.12 (vi) 0.02

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\frac{7}{9}

- \frac{8}{11}

\frac{12}{7}

- \frac{13}{8}

2 \frac{2}{5}

3 \frac{1}{4}

Find the surface area of a cube whose edge is
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2.1

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