Question

Find the cubes of :
(i) 2.1
(ii) 0.4
(iii) $\frac{3}{2}$ [3 Marks]

Answer 1

(i) (2.1)³ = $\frac{(21\times 21\times 21)}{(10\times 10\times 10)}=\frac{9261}{1000}=9.261$
[1 mark]
(ii) (0.4)³ = $\frac{4\times 4\times 4}{10\times 10\times 10}=\frac{64}{1000}=0.064$
[1 mark]
(iii)($\frac{3}{2}$)³ = $\frac{3\times 3\times 3}{2\times 2\times 2}=\frac{27}{8}=3.375$...[1 mark]