Find the cubes of- i 3-7 ii 8-9 iii 10-13 iv 12-7 v 21-2

(i)3/7= ( 3/7 )^3=3× 3× 3/7× 7× 7=27/343 (ii)8/9= (8/9 )^3=8× 8× 8/9× 9× 9=512/729 (iii)10/13= ( 10/13 )^3=10 × 10× 10/13× 13× 13=1000/2197 (iv)12/7= ( 12/7 )^3 ...

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Byju's Answer

Standard VIII

Mathematics

Cube Numbers

Find the cube...

Question

Find the cubes of:

(i) $\frac{3}{7}$ (ii) $\frac{8}{9}$ (iii) $\frac{10}{13}$

(iv) $1 \frac{2}{7}$ (v) $2 \frac{1}{2}$

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Solution

$(i) \frac{3}{7} = {(\frac{3}{7})}^{3} = \frac{3 \times 3 \times 3}{7 \times 7 \times 7} = \frac{27}{343} (i i) \frac{8}{9} = {(\frac{8}{9})}^{3} = \frac{8 \times 8 \times 8}{9 \times 9 \times 9} = \frac{512}{729} (i i i) \frac{10}{13} = {(\frac{10}{13})}^{3} = \frac{10 \times 10 \times 10}{13 \times 13 \times 13} = \frac{1000}{2197} (i v) 1 \frac{2}{7} = {(1 \frac{2}{7})}^{3} = {(\frac{1 \times 7 + 2}{7})}^{3} = {(\frac{9}{7})}^{3} = \frac{9 \times 9 \times 9}{7 \times 7 \times 7} = \frac{729}{343} = 2 \frac{43}{343} (v) 2 \frac{1}{2} = {(2 \frac{1}{2})}^{3} = {(\frac{5}{2})}^{3} = \frac{5 \times 5 \times 5}{2 \times 2 \times 2} = \frac{125}{8} = 15 \frac{5}{8}$

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Similar questions

Arrange the following in ascending order.

i. $21 \times (- 34) \times (- 12)$

ii. $(7 \times 8) - 9$

iii. $7 \times (8 - 9)$

iv. $21 \times (- 34) \times (12)$

Find the cubes of :

(i) -3 (ii) -7 (iii) -12

(iv) -12 (v) -18 (vi) -25

(vii) -50

Fill in the blanks.

(i) $(\frac{- 3}{17}) + (\frac{- 12}{5}) = (\frac{- 12}{5}) + (. . . . .)$

(ii) $- 9 + \frac{- 21}{8} = (. . . . . .) + (- 9)$

(iii) $(\frac{- 8}{13} + \frac{3}{7}) + (\frac{- 13}{4}) = (. . . . . .) + [\frac{3}{7} + (\frac{- 13}{4})]$

(iv) $- 12 + (\frac{7}{12} + \frac{- 9}{11}) = (- 12 + \frac{7}{12}) + (. . . . .)$

(v) $\frac{19}{- 5} + (\frac{- 3}{11} + \frac{- 7}{8}) = {\frac{19}{- 5} + (. . . . .)} + \frac{- 7}{8}$

(vi) $\frac{- 16}{7} + . . . . . = . . . . . . + \frac{- 16}{7} = \frac{- 16}{7}$

Multiply :
$(i) \frac{5}{6} and \frac{8}{9} (i i) \frac{2}{7} and \frac{- 14}{9} (i i i) \frac{- 7}{8} and 4 (i v) \frac{36}{- 7} and \frac{- 9}{28} (v) \frac{- 7}{10} and \frac{- 8}{15} (v i) \frac{3}{- 2} and \frac{- 7}{3}$

Question 1(iii)
Find the value of:
(iii) $11^{2}$

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Find the cubes of: (i) 37 (ii) 89 (iii) 1013 (iv) 127 (v) 212

(i)37=(37)3=3×3×37×7×7=27343(ii)89=(89)3=8×8×89×9×9=512729(iii)1013=(1013)3=10×10×1013×13×13=10002197(iv)127=(127)3=(1×7+27)3=(97)3=9×9×97×7×7=729343=243343(v)212=(212)3=(52)3=5×5×52×2×2=1258=1558

Find the cubes of:

(i) $\frac{3}{7}$ (ii) $\frac{8}{9}$ (iii) $\frac{10}{13}$

(iv) $1 \frac{2}{7}$ (v) $2 \frac{1}{2}$