Question

Find the cubes of the following numbers:
(i) 7
(ii) 12
(iii) 16
(iv) 21
(v) 40
(vi) 55
(vii) 100
(viii) 302
(ix) 301

Answer 1

Cube of a number is given by the number raised to the power three.

(i) $\mathrm{Cube}\mathrm{of}7=7^3=7\times 7\times 7=343$

(ii) $\mathrm{Cube}\mathrm{of}12={12}^3=12\times 12\times 12=1728$

(iii) $\mathrm{Cube}\mathrm{of}16={16}^3=16\times 16\times 16=4096$

(iv) $\mathrm{Cube}\mathrm{of}21={21}^3=21\times 21\times 21=9261$

(v) $\mathrm{Cube}\mathrm{of}40={40}^3=40\times 40\times 40=64000$

(vi) $\mathrm{Cube}\mathrm{of}55={55}^3=55\times 55\times 55=166375$

(vii) $\mathrm{Cube}\mathrm{of}100={100}^3=100\times 100\times 100=1000000$

(viii) $\mathrm{Cube}\mathrm{of}302={302}^3=302\times 302\times 302=27543608$

(ix) $\mathrm{Cube}\mathrm{of}301={301}^3=301\times 301\times 301=27270901$