Find the current flowing across three resistors $3 Ω, 5 Ω$ and $2 Ω$ connected in parallel to a $15$ V supply. Also find the effective resistance and total current drawn from the supply.

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Solution

Given data:
$R_{1} = 3 Ω, R_{2} = 5 Ω, R_{3} = 2 Ω$ ; supply voltage $V = 15$ volt.
Solution:
Effective resistance of parallel combination.
$\frac{1}{R_{P}} = \frac{1}{R_{1}} + \frac{1}{R_{2}} + \frac{1}{R_{3}} = \frac{1}{3} + \frac{1}{5} + \frac{1}{2}$
$R_{p} = 0.9677 Ω$
Current through $R_{1}, I_{1} = \frac{V}{R_{1}} = \frac{15}{3} = 5 A$
Current through $R_{2}, I_{2} = \frac{V}{R_{2}} = \frac{15}{5} = 3 A$
Current through $R_{3}, I_{3} = \frac{V}{R_{3}} = \frac{15}{2} = 7.5$ A
Total current I $= \frac{V}{R_{P}} = \frac{15}{0.9677}$
$=$
$15.5$ A

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