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Standard XII

Physics

Current Density Vector

Find the curr...

Question

Find the current flowing through a copper wire of length $0.2 m$ , area of cross-section $1 {mm}^{2}$ , when connected to a battery of $4 V$ . Given that electron mobility $= 4.5 \times 10^{- 6} \frac{m^{2}}{Vs}$ and charge on electron $= 1.6 \times 10^{- 19} C .$ The number density of electron in copper is $8.5 \times 10^{28} m^{- 3}$ .

1.22 A

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2.12 A

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4.52 A

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4.68 A

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Solution

The correct option is A $1.22 A$
Current through a conductor is given by $I = n e A V_{d}$

Substituting the data given in the question ,
$I = 8.5 \times 10^{28} \times 10^{- 6} \times 1.6 \times 10^{- 19} \times 4.5 \times 10^{- 6} \times 20$

$= 1.22 A$

Hence, option (c) is the correct answer.

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Similar questions

The number density of electron in copper is 8.5 × 10²⁸ m^-3. What is the current flowing through a copper wire of length 0.2 m, area of cross-section 1 mm² when connected to a battery of 4.0 V? Given that electron mobility = 4.5 × 10^-6 m²V^-1s^-1 and charge on the electron is 1.6 × 10^-19 C.

Q. Drift speed of electrons, when

1.5 A

of current flows in a copper wire of cross-section

5 {mm}^{2}

, is

v

. If the electron density in copper is

9 \times 10^{28} m^{- 3}

the value of

v

{mm s}^{- 1}

close to

(Take charge of electron to be = 1.6 \times 10^{- 19} C

)

Q. Drift speed of electrons, when

1.5 A

of current flows in a copper wire of cross section

5 m m 2

, is

v

. If the electron density in copper is

9 \times 10^{28} / m^{3}

the value of

v

m m / s

is close to (Take charge of electron to be

= 1.6 \times 10^{- 19} C

)

Q. Drift speed of electron, when 1.5 A of current flows in a copper wire of cross section

5 m m^{2} i s v

. If the electron density in copper

9 \times 10^{28} / m^{3}

the value of

v i n m m / s

is close to (Take charge of electron to be

= 1.6 \times 10^{- 19} C

)

A copper wire has a cross sectional area of $1 m m^{2}$ . The electron density of copper is $8.5 \times 10^{28} m^{3}$ . Calculate the mean drift velocity of the electrons through the wire when the current is 3 A.

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Find the current flowing through a copper wire of length 0.2 m, area of cross-section 1 mm2, when connected to a battery of 4 V. Given that electron mobility =4.5×10−6 m2Vs and charge on electron =1.6×10−19 C. The number density of electron in copper is 8.5×1028 m−3.

The correct option is A 1.22 ACurrent through a conductor is given by I=neAVd Substituting the data given in the question , I=8.5×1028×10−6×1.6×10−19×4.5×10−6×20 =1.22 A Hence, option (c) is the correct answer.

The correct option is A $1.22 A$
Current through a conductor is given by $I = n e A V_{d}$

Substituting the data given in the question ,
$I = 8.5 \times 10^{28} \times 10^{- 6} \times 1.6 \times 10^{- 19} \times 4.5 \times 10^{- 6} \times 20$

$= 1.22 A$

Hence, option (c) is the correct answer.