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Question

Find the current flowing through the resistance R1 of the circuit shown in the figure. The resistance are equal to R1=10 Ω, R2=20 Ω and R3=30 Ω and the potentials of points 1,2 and 3 are given as V1=10 V ,V2=6 V and V3=5 V.


A
0.1 A
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B
0.2 A
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C
0.3 A
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D
0.4 A
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Solution

The correct option is B 0.2 A

Considering the potential at junction O to be equal to x and writing <!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Kirchhoff's Junction Law equation at this junction,

x1010+x530+x620=0

6x60+2x10+3x18=0

11x=88

x=8 V

Current through resistance R1 is ,

I1=10xR1=10810=0.2 A

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, (B) is the correct answer.

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