Find the current flowing through the resistance R1 of the circuit shown in the figure. The resistance are equal to R1=10Ω,R2=20Ω and R3=30Ω and the potentials of points 1,2 and 3 are given as V1=10V,V2=6V and V3=5V.
A
0.1A
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B
0.2A
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C
0.3A
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D
0.4A
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Solution
The correct option is B0.2A
Considering the potential at junction O to be equal to x and writing
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Kirchhoff's Junction Law equation at this junction,
x−1010+x−530+x−620=0
⇒6x−60+2x−10+3x−18=0
⇒11x=88
∴x=8V
Current through resistance R1 is ,
I1=10−xR1=10−810=0.2A
<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}-->
Hence, (B) is the correct answer.