Find the current flowing through the resistance R1 of the circuit shown in the figure- The resistance are equal to R1-10 - - R2-20 - and R3-30 - and the potentials of points 1-2 and 3 are given as V1-10 V -V2-6 V and V3-5 V-

Considering the potential at junction O to be equal to x and writing lt;!–td border: 1px solid #ccc;br mso data placement:same cell;– gt; Kirchhoff's Jun ...

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Standard XII

Physics

Mutual Induction

Find the curr...

Question

Find the current flowing through the resistance $R_{1}$ of the circuit shown in the figure. The resistance are equal to $R_{1} = 10 Ω, R_{2} = 20 Ω$ and $R_{3} = 30 Ω$ and the potentials of points $1, 2$ and $3$ are given as $V_{1} = 10 V, V_{2} = 6 V$ and $V_{3} = 5 V$ .

0.1 A

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0.2 A

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0.3 A

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0.4 A

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Solution

The correct option is B $0.2 A$

Considering the potential at junction $O$ to be equal to $x$ and writing  Kirchhoff's Junction Law equation at this junction,

$\frac{x - 10}{10} + \frac{x - 5}{30} + \frac{x - 6}{20} = 0$

$\Rightarrow 6 x - 60 + 2 x - 10 + 3 x - 18 = 0$

$\Rightarrow 11 x = 88$

$∴ x = 8 V$

Current through resistance $R_{1}$ is ,

$I_{1} = \frac{10 - x}{R_{1}} = \frac{10 - 8}{10} = 0.2 A$

 Hence, $(B)$ is the correct answer.

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Mutual Induction

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Find the current flowing through the resistance R1 of the circuit shown in the figure. The resistance are equal to R1=10 Ω, R2=20 Ω and R3=30 Ω and the potentials of points 1,2 and 3 are given as V1=10 V ,V2=6 V and V3=5 V.

Find the current flowing through the resistance $R_{1}$ of the circuit shown in the figure. The resistance are equal to $R_{1} = 10 Ω, R_{2} = 20 Ω$ and $R_{3} = 30 Ω$ and the potentials of points $1, 2$ and $3$ are given as $V_{1} = 10 V, V_{2} = 6 V$ and $V_{3} = 5 V$ .