Question

Find the current through $20\Omega$ resistance in following circuit diagram.

Answer 1

Total equivalent Resistance is

$\begin{array}{c}\frac{1}{R_{eq}}\frac{1}{10}+\frac{1}{10}+\frac{1}{20}+\frac{1}{30}+\frac{1}{30}+\frac{1}{120}\\ \frac{2}{10}+\frac{1}{20}+\frac{2}{30}+\frac{1}{120}\\ \frac{12+3+4}{60}+\frac{1}{120}\\ \frac{19}{60}+\frac{1}{120}\\ \frac{38+1}{120}=\frac{39}{120}\\ R_{eq}=\frac{120}{39}\\ currentcross20\Omega is\\ I=\frac{V}{R}=\frac{100}{20}\\ I=5A\end{array}$