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Question

Find the current through the 10Ω resistor shown in figure:
758917_e5bb28adbdc44071bda8080b06f305da.png

A
0.5A
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B
1A
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C
2A
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D
5A
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Solution

The correct option is A 0.5A
Given circuit
Applying KVL in loop 1
4.5+3i1+6(i1i2)=0
3i1+6i16i2=4.59i16i2=4.5 ___(1)
KVL in loop 2
3v+10i2+6(i2i1)=0
6i1=16i2=3v __(2)
solving (1) & (2)
9i16i2=4.518i112i2=9
6i1+16i2=318i1+48i2=9
36i2=18=i2=18/36=1/2=0.5A
6i1+16(1/2)=3v
6i1=38
i=5/6=0.833
The current flowing through 10Ω resister is 0.5A

1186813_758917_ans_f81120927d6748e29639627229ae7b74.png

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