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Byju's Answer
Standard XII
Physics
Mixed Combination of Cells
Find the curr...
Question
Find the current through the
10
Ω
resistor shown in figure:
A
0.5
A
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B
1
A
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C
2
A
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D
5
A
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Solution
The correct option is
A
0.5
A
Given circuit
Applying KVL in loop 1
−
4.5
+
3
i
1
+
6
(
i
1
−
i
2
)
=
0
⇒
3
i
1
+
6
i
1
−
6
i
2
=
4.5
⇒
9
i
1
−
6
i
2
=
4.5
___(1)
KVL in loop 2
−
3
v
+
10
i
2
+
6
(
i
2
−
i
1
)
=
0
⇒
−
6
i
1
=
16
i
2
=
3
v
__(2)
solving (1) & (2)
9
i
1
−
6
i
2
=
4.5
⇒
18
i
1
−
12
i
2
=
9
−
6
i
1
+
16
i
2
=
3
⇒
−
18
i
1
+
48
i
2
=
9
36
i
2
=
18
=
i
2
=
18
/
36
=
1
/
2
=
0.5
A
−
6
i
1
+
16
(
1
/
2
)
=
3
v
−
6
i
1
=
3
−
8
i
=
5
/
6
=
0.833
∴
The current flowing through
10
Ω
resister is
0.5
A
Suggest Corrections
0
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