Question

Find the current through the $10\Omega$ resistor shown in figure.

• A. $0\text{A}$
• B. $5\text{A}$
• C. $7\text{A}$
• D. $9\text{A}$

Answer 1

The correct option is A $0\text{A}$

Let's redraw the figure and let's assume potential across $6\text{ohm}$ resistor to be $0\text{V}$ and $x\text{V}$ respectively.


Apply KCL at $x\text{V}$ junction,

$i_1+i_2+i_3=0$

$\frac{x-3}{10}+\frac{x-0}{6}+\frac{x-4.5}{3}=0$

$\Rightarrow x=3\text{V}$

So, $i_1=\frac{3-3}{10}=0\text{A}$

Hence, option $\left(a\right)$ is correct.