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Inductive Reactance

Find the curr...

Question

Find the current through the resistance R in figure if (a) R = 12Ω (b) R = 48Ω.

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Solution

(a) When R = 12 Ω:

The 4 V battery is forward biassing the diode and the 6 V battery is reverse biassing the diode, so the diode is effectively reverse biassed. It acts like an open circuit so that no current flows through this branch. Hence, to simplify the circuit, this branch can be removed.

The current through R on applying the KVL in the circuit is given by
$i = \frac{10}{24} = 0.4166 = 0.42 A$

(b) Similarly, for R = 48 Ω,
$i = \frac{10}{48 + 12} = \frac{10}{60} = 0.16 A$

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