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Question

Find the currents in branches 1, 2 and 3.

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A
( 2,1,1 ) A
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B
( 2,2,2 ) A
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C
( 4,7,5 ) A
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D
( 0,8,6 ) A
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Solution

The correct option is A ( 2,1,1 ) A
Here the current in the branch 2 is I2=1A
now apply KCL at node B , I3+34=0 or I3=1A
and at node A, I1I2I3=0 or I1=I2+I3=1+1=2A
Thus current at branches 1 , 2 and 3 are ( 2 , 1 , 1 ) A

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