Question

Find the curved surface area of a frustum cone whose larger and smaller radius is 12.2 and 8.8 ft. The slant height is 5.2 ft. (Use $\pi$ = 3.14)

• A. 342.888 ft${}^2$
• B. 348.75 ft${}^2$
• C. 338.75 ft${}^2$
• D. 328.75 ft${}^2$

Answer 1

The correct option is A 342.888 ft${}^2$

Curved surface area of a frustum cone = $\pi$(r + R)s

= 3.14 $\times$ (12.2 + 8.8) $\times$ 5.2

= 3.14 $\times$ (21) $\times$ 5.2

Curved surface area of a frustum cone = 342.888 ft${}^2$