Find the curved surface area of frustum cone radii 0.2 and 3.2 cm and a slant height 5 cm. (Use $π$ = 3.14).

53.38

c m^{2}

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52.38

c m^{2}

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51.38

c m^{2}

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50.38

c m^{2}

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Solution

The correct option is A 53.38 $c m^{2}$
Curved surface area = $π (R + r) s$
= $π (3.2 + 0.2) \times 5$
= $3.14 \times (3.4) \times 5$
= $3.14 \times 17$
= 53.38 $c m^{2}$

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Find the curved surface area of frustum cone radii 0.2 and 3.2 cm and a slant height 5 cm. (Use π = 3.14).

The correct option is A 53.38 cm2Curved surface area = π(R+r)s= π(3.2+0.2)×5= 3.14×(3.4)×5= 3.14×17= 53.38 cm2

Find the curved surface area of frustum cone radii 0.2 and 3.2 cm and a slant height 5 cm. (Use $π$ = 3.14).

The correct option is A 53.38 $c m^{2}$
Curved surface area = $π (R + r) s$
= $π (3.2 + 0.2) \times 5$
= $3.14 \times (3.4) \times 5$
= $3.14 \times 17$
= 53.38 $c m^{2}$