Find the curved surface area of frustum cone radii 12 and 6 cm and a slant height 20 cm.

350 π c m^{2}

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360 π c m^{2}

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370 π c m^{2}

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380 π c m^{2}

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Solution

The correct option is C $360 π c m^{2}$
Curved surface area $= π (R + r) s$
= $π (12 + 6) \times 20$
= $π (18) \times 20$
= 360 $π c m^{2}$

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Question 13
The radii of the top and bottom of a bucket of slant height 45 cm are 28 cm and 7 cm, respectively. The curved surface area of the bucket is

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Find the curved surface area of frustum cone radii 12 and 6 cm and a slant height 20 cm.

The correct option is C 360π cm2Curved surface area =π(R+r)s= π(12+6)×20= π(18)×20= 360 πcm2

The correct option is C $360 π c m^{2}$
Curved surface area $= π (R + r) s$
= $π (12 + 6) \times 20$
= $π (18) \times 20$
= 360 $π c m^{2}$