Question

Find the cut off wavelength for the continuous X-rays coming from an X-ray tube operating at 30 kV.

Answer 1

V= 30 KV

$\lambda =\frac{hc}{E}=\frac{hc}{eV}$

= $\frac{1242eV-nm}{e\times 30\times {10}^3}$

= 414 $\times {10}^{-4}$ nm = 41.4 Pm