Question

Find the cutoff wavelength for the continuous $x$ rays coming from $x$ rays tube operating at $40kv$

Answer 1

Given that,

$V=40V$

We know that,

$\lambda =\frac{hc}{E}$

$\lambda =\frac{hc}{eV}$

$\lambda =\frac{1242eV-nm}{e\times 40\times {10}^{3}V}$

$\lambda =31.1\times {10}^{-3}$

$\lambda =311\times {10}^{-4}nm$

Hence, the cutoff wave length is $311\times {10}^{-4}nm$