Question

Find the day of the week on 18 July, 1776 (leap year).

• A. Monday
• B. Tuesday
• C. Wednesday
• D. Thursday

Answer 1

The correct option is D Thursday

Here $1600$ years have '0' odd day.................. (A)
$100$ years have '5' odd days................. (B).
$75$ years = (18 leap years + 57 ordinary years)
$=(18\times 2+57\times 1)$
$=93$ odd days
$=(7\times 13+2)=2$ odd days ....................(C)
Now, the number of days from 1st January to 18 July, 1776
$=182+18=200$ days
$=(28\times 7+4)$ days $=4$ odd days ....................(D)
Adding (A) + (B) +(C) +(D),
We get, $0+5+2+4=4$ odd days
Hence, the day is Thursday.