Find the de-Broglie wavelength of an electron with kinetic energy of 120 eV
112 pm
95 pm
124 pm
102 pm
λ=hp
where, h=Plank's constant, P=Momentum
Also, P=√2mk
λ=h√2mk
Putting values we get,
λ≈112pm
The kinetic energy of an electron with de-Broglie wavelength of 0.3 nanometer is