wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the decay rate of the substance having 4×1015 atoms. Half-life of a radioactive substance in α decay is 1.2×107

A
2.3×108 atom/s
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
3.2×108 atom/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2.3×1011 atom/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
3.2×1011 atom/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 2.3×108 atom/s
N=4×1015atoms
half life is t1/2=1.2×107second
so the decay constant will be λ=0.693t1/2=0.5775×107/s
Now the the decay rate can be calculated as A=Nλ=4×1015×0.5775×107atoms/s=2.31×108atoms/s

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon