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Question

Find the decay rate of the substance having 4×1015 atoms. Half-life of a radioactive substance in α decay is 1.2×107

A
2.3×108 atom/s
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B
3.2×108 atom/s
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C
2.3×1011 atom/s
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D
3.2×1011 atom/s
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Solution

The correct option is A 2.3×108 atom/s
N=4×1015atoms
half life is t1/2=1.2×107second
so the decay constant will be λ=0.693t1/2=0.5775×107/s
Now the the decay rate can be calculated as A=Nλ=4×1015×0.5775×107atoms/s=2.31×108atoms/s

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