Find the degree of the differential equation- d2xdy2-a2x-0

The correct option is A 1 given differential equation is d ^ 2 y d x ^ 2 + a ^ 2 x ^ 2 =0 This equation is in pure polynomial form containg no Tra ...

You visited us 5 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Mathematics

Homogeneous Differential Equation

Find the degr...

Question

Find the degree of the differential equation: $\frac{d^{2} x}{d y^{2}} + a^{2} x = 0$

1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $1$
given differential equation is $\frac{d^{2} y}{d x^{2}} + a^{2} x^{2} = 0$
This equation is in pure polynomial form containg no Trancendental functions.
The power of the order term in the Differential equation is $1$ .
$∴$ Degree of the differential equation is $1$ .

Suggest Corrections

Similar questions

Q. The degree of the differential equation

\frac{d^{2} x}{d t^{2}} + 2 x^{3} = 0

Q. Write the degree of the differential equation

x^{3} {(\begin{matrix} \frac{d^{2} y}{d x^{2}} \end{matrix})}^{2} + x {(\begin{matrix} \frac{d y}{d x} \end{matrix})}^{4} = 0

The degree of the differential equation ${(\frac{d^{2} y}{d x^{2}})}^{3} + {(\frac{d y}{d x})}^{2} + s i n (\frac{d y}{d x}) + 1 = 0$ is
(a) 3
(b) 2
(c) 1
(d) None of these

State the order and degree of the given differential equation, if the order is a and degree is b, find a+b.

{[\frac{d^{2} x}{d t^{2}}]}^{3} + [\frac{d x}{d t}] - x t = 0

Q. The degree and the order of the differential equation

y = x {(\frac{d y}{d x})}^{2} + {(\frac{d x}{d y})}^{2}

are respectively:

Join BYJU'S Learning Program

Find the degree of the differential equation: d2xdy2+a2x=0

The correct option is A 1given differential equation is d2ydx2+a2x2=0This equation is in pure polynomial form containg no Trancendental functions.The power of the order term in the Differential equation is 1.∴ Degree of the differential equation is 1.

Find the degree of the differential equation: $\frac{d^{2} x}{d y^{2}} + a^{2} x = 0$

The correct option is A $1$
given differential equation is $\frac{d^{2} y}{d x^{2}} + a^{2} x^{2} = 0$
This equation is in pure polynomial form containg no Trancendental functions.
The power of the order term in the Differential equation is $1$ .
$∴$ Degree of the differential equation is $1$ .