Find the degree of the differential equation- -1-x2-dydx

The correct option is B 1 GIven differential equation is √( 1+x^ 2 ) = dy dx This differential equation is in pure polynomial form containing no tra ...

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Standard XII

Mathematics

Homogeneous Differential Equation

Find the degr...

Question

Find the degree of the differential equation: $\sqrt{1 + x^{2}} = \frac{d y}{d x}$

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Solution

The correct option is B $1$
GIven differential equation is $\sqrt{1 + x^{2}} = \frac{d y}{d x}$
This differential equation is in pure polynomial form containing no trancendental functions.
$∴$ the power of the order term is the degree of the differential equation.
$∴$ the degree is $1$ .

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Similar questions

The degree of the differential equation ${(\frac{d^{2} y}{d x^{2}})}^{3} + {(\frac{d y}{d x})}^{2} + s i n (\frac{d y}{d x}) + 1 = 0$ is
(a) 3
(b) 2
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Q. The degree of the differential equation

x = 1 + (\begin{matrix} \frac{d y}{d x} \end{matrix}) + \frac{1}{2!} {(\begin{matrix} \frac{d y}{d x} \end{matrix})}^{2} + \frac{1}{3!} {(\begin{matrix} \frac{d y}{d x} \end{matrix})}^{3} + \dots

Q. The degree of the differential equation

x = 1 + (\frac{d y}{d x}) + \frac{1}{2!} {(\frac{d y}{d x})}^{2} + \frac{1}{3!} {(\frac{d y}{d x})}^{3} + . . . .

Q. The degree of differential equation

x = 1 + (\frac{d y}{d x}) + \frac{1}{2!} {(\frac{d y}{d x})}^{2} + \frac{1}{3!} {(\frac{d y}{d x})}^{3} + . . .

is :

Q. Find degree and order of the differential equation.

x + (\frac{d y}{d x}) = \sqrt{1 + {(\frac{d y}{d x})}^{2}}

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Find the degree of the differential equation: √1+x2=dydx

The correct option is B 1GIven differential equation is √1+x2=dydxThis differential equation is in pure polynomial form containing no trancendental functions.∴ the power of the order term is the degree of the differential equation.∴ the degree is 1.

Find the degree of the differential equation: $\sqrt{1 + x^{2}} = \frac{d y}{d x}$

The correct option is B $1$
GIven differential equation is $\sqrt{1 + x^{2}} = \frac{d y}{d x}$
This differential equation is in pure polynomial form containing no trancendental functions.
$∴$ the power of the order term is the degree of the differential equation.
$∴$ the degree is $1$ .