Question

Find the degree of the polynomial $3\sqrt{y}+y^2$

• A. $3$
• B. $\frac{3}{2}$
• C. $2$
• D. The expression is not a polynomial

Answer 1

The correct option is D The expression is not a polynomial

A polynomial function is a function such as a quadratic, a cubic, a quartic, and so on, involving only non-negative integer powers of x.

The given function $3\sqrt{y}+y^2$ can be written as $3y^{\frac{1}{2}}+y^2$.

The given function contains non-integer power($\frac{1}{2}$) of $x$ and thus, it can't be a polynomial function.

Hence, option D is correct.