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Bulk Modulus

Find the dens...

Question

Find the density of water $2 k m$ deep in sea. $B u l k m o d u l u s = 2 \times 10^{9} P a$

10^{3} k g m^{- 3}

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1010 k g m^{- 3}

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1100 k g m^{- 3}

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1040 k g m^{- 3}

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Solution

The correct option is B $1010 k g m^{- 3}$
$\frac{Δ V}{V} = \frac{P}{B} = \frac{2 \times 10^{3} \times 10^{3} \times 10}{2 \times 10^{9}} = .01$
$\frac{Δ V}{V} = \frac{Δ δ}{δ} o r Δ δ = 10 k g / m^{3}$
$∴ d e n s i t y o f w a t e r = 1010 k g m^{- 3}$

Suggest Corrections

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