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Basic Inverse Trigonometric Functions

Find the deri...

Question

Find the derivative of $f$ given by $f (x) = {sin}^{- 1} x$ assuming it exists.

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Solution

Given that

$f (x) = {sin}^{- 1} x$

$\Rightarrow f^{'} (x) = \frac{1}{\sqrt{1 - x^{2}}}$

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Similar questions

f (x) = sin (x^{2})

f (x) = (1 + x) (1 + x^{2}) (1 + x^{4}) (1 + x^{8})

f (0) = 0

lim x \to 0 \frac{f (x)}{x}

L

f^{'} (0)

f

x

x = 0

L

x_{0}

y = f (x)

f (x) = (1 + x) (1 + x^{2}) (1 + x^{4}) (1 + x^{8})

f^{'} (1) .

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