Question

Find the derivative of $(9x^2+\frac{3}{x}+5sinx)$ with respect to x.

Answer 1

We have $\frac{d}{dx}(9x^2+\frac{3}{x}+5sinx)$

$=9.\frac{d}{dx}\left(x^2\right)+3.\frac{d}{dx}\left(x^{-1}\right)+5.\frac{d}{dx}\left(sinx\right)$

$=9\times 2x+3.(-1)x^{-2}+5cosx=18x-\frac{3}{x^2}+5cosx.$