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Question

Find the derivative of log(sin(logx)).

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Solution

Let p=log[sin(logx)]
Differentiating P wrt x we have
dpdx=ddx[log(sin(logx))]
dpdx=1sin(logx)cos(logx)×1x
[dpdx=cot(logx)x].

1204150_1399134_ans_8d4a818425cc42a28b5c9c58cfe10620.JPG

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Logarithmic Differentiation
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