Find the derivative of $sin 2 x cos 3 x$

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Solution

$y = s i n 2 x c o s 3 x$

$(\frac{d y}{d x}) = \frac{d (s i n 2 x c o s 3 x)}{d x}$

$= (\frac{d s i n 2 x}{d x}) c o s 3 x + s i n 2 x (\frac{d c o s 3 x}{d x})$
$= [(c o s 2 x) \times 2] c o s 3 x + s i n 2 x \times (- s i n 3 x) \times 3$

$= 2 c o s 2 x c o s 3 x - 3 s i n 2 x s i n 3 x$

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