Question

Find the derivative of the following function:
f(x)= $si{n}^{n}x$

Answer 1

Here, $f\left(x\right)=si{n}^{n}x$

$\therefore f^{\prime }\left(x\right)=\frac{d}{dx}\left(si{n}^{n}x\right)$

$=nsi{n}^{n-1}x.\frac{d}{dx}\left(sinx\right)$

$=nsi{n}^{n-1}x.cosx$