CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the derivative of the following function
f(x)=sin(2x2+4x+3)

A
cos(2x2+4x+3)(4x+4xln4)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
cos(2x2+4x+3)(4x+4xln4)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
cos(2x2+4x+3)(4x+4x)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
cos(2x2+4x+3)(4x+4x)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B cos(2x2+4x+3)(4x+4xln4)
f(x)=sin(2x2+4x+3)
f'(x)=d(sin(2x2+4x+3))dx×d(2x2+4x+3)dx
f'(x)=cos(2x2+4x+3)×(4x+4xln(4))

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Basic Theorems in Differentiation
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon