Find the derivative of the following functions from first principle x3−27
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Solution
Let f(x)=x3−27 According to the first principle, f′(x)=limh→0f(x+h)−f(x)h = limh→0[(x+h)3−27]−(x3−27)h = limh→0x3+h3+3x2h+3xh2−x3h = limh→0h3+3x2h+3xh2h = limh→0(h2+3x2+3xh) = 0+3x2+0=3x2