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Question

Find the derivative of the following functions from first principle
x327

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Solution

Let f(x)=x327
According to the first principle,
f(x)=limh0f(x+h)f(x)h
= limh0[(x+h)327](x327)h
= limh0x3+h3+3x2h+3xh2x3h
= limh0h3+3x2h+3xh2h
= limh0(h2+3x2+3xh)
= 0+3x2+0=3x2

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