wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the derivative of xn+axn1+a2xn2+...+an1x+an for some fixed real number a.

Open in App
Solution

Here f(x) = xn+axn1+a2xn2+...+an1x+anf(x)=ddx[xn+ann1+a2xn2+...+xn1+an]

= ddx(xn)+addx(xn1)+a2ddx(xn2)+...+an1ddx(x)+ddx(an)

= nxn1+a(n1)xn2+a2(x2)xn3+...+an1+0

= nxn1+a(n1)xn2+a2(n2)xn3+...+an1


flag
Suggest Corrections
thumbs-up
15
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Summation by Sigma Method
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon