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Question

Find the derivative of y=esinθ with respect to θ

A
ecosθ(sinθ)
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B
esinθ(cosθ)
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C
etanθ(sinθ)
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D
ecosθ(cotθ)
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Solution

The correct option is B esinθ(cosθ)
Given: y=esinθ
Using chain rule we have
y=desinθdsinθ×dsinθdθ
y=esinθ(cosθ)

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