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Question

Find the derivative with respect to x of the function(logcosxsinx)(logsinxcosx)1+sin12x1+x2atx=π4

A
8(4π2+161log2).
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B
8(4π2+16+1log2).
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C
8(4π2+161log2).
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D
8(4π2+16+1log2).
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Solution

The correct option is A 8(4π2+161log2).
Let y=(logcosxsinx)(logsinxcosx)1+sin12x1+x2
=(logcosxsinx)2+2tan1x[logba=1logab] =(logesinxlogecosx)2+2tan1x.
dydx=2(logsinxlogcosx)cotx.logcosx+tanxlogsinx(logcosx)2+21+x2
Hence at x=π4. we have dydx=2.log(1/2)log(1/2)1.log(1/2)+1.log(1/2)[log(1/2)]2+21+(π2/16)=8log2+32π2+16
=8(4π2+161log2).

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