wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the derivatives of
sin(2x+3)

Open in App
Solution

Let y=sin(2x+3)

dydx=cos(2x+3)ddx(2x+3)

dydx=cos(2x+3)(2)

dydx=2cos(2x+3)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Range of Trigonometric Ratios from 0 to 90
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon