Question

Find the derivatives of the following:
$\sin x\cos x$.

Answer 1

Let

$y=\sin x\cos x$

On differentiating w.r.t $x$, we get

$\frac{dy}{dx}=\cos x\cos x+\sin x(-\sin x)$

$\frac{dy}{dx}={\cos }^{2}x-{\sin }^{2}x$

$\frac{dy}{dx}=\cos 2x$

Hence, this is the answer.