Question

Find the diameter of a wheel that makes $113$ revolutions to go $2km26dm$. $(\pi =\frac{22}{7})$

• A. $6\frac{4}{11}m$
• B. $7\frac{5}{11}$
• C. $6\frac{6}{11}$
• D. $7\frac{1}{11}$

Answer 1

The correct option is A $6\frac{4}{11}m$

$2km26dam=(2\times 1000+26\times 10)m$ $=2260m$

113 revolutions are equivalent to 2260 m $\Rightarrow$ 1 revolution is equivalent to $\frac{2260}{113}m=20m$
$\Rightarrow \pi \times diameter=20m\Rightarrow \frac{22}{7}\times diameter=20m$
$\Rightarrow diameter=\frac{20\times 7}{22}=\frac{70}{11}m=6\frac{4}{11}m$