Find the diameter of the circle whose area is equal to the sum of the areas of two circles having radii 4 cm and 3 cm.
Let r1 and r2 be the radius of the given circle.
Suppose, r is the radius of the circle whose area is equal to the sum of the areas of the circle.
πr2 = πr21 +πr22
⇒ r2 = r21 +r22
⇒ r2 = 42 +32
⇒ r2 = 25
⇒ r = 5 cm
∴ Diameter of the circle = 2r = 2 × 5 cm = 10 cm