Question

Find the difference:
$\frac{5}{6}-\frac{4}{9}$

Answer 1

$\frac{5}{6}-\frac{4}{9}$

$$\begin{gathered} 3\underline{\overline{)6,9}} \\ 2\underline{\overline{)2,3}} \\ 3\underline{\overline{)1,3}} \\ \underline{\overline{)1,1}} \end{gathered}$$
L.C.M. of 6 and 9 = (3 $\times$ 2 $\times$ 3) = 18
Now, we have:
$$\begin{gathered} \frac{5}{6}=\frac{5\times 3}{6\times 3}=\frac{15}{18};\frac{4}{9}=\frac{4\times 2}{9\times 2}=\frac{8}{18} \\ \therefore \frac{5}{6}-\frac{4}{9}=\frac{15}{18}-\frac{8}{18}=\frac{\left(15-8\right)}{18}=\frac{7}{18} \end{gathered}$$