Find the difference between the $25^{t h}$ term and the $15^{t h}$ term of the progression $- 13, - 17, - 21$ .....

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Solution

Given progression -13, -17, -21 ..... is in A.P.
d = -4
The required difference = |t25−t15| =
∴ |(a + 24d) - (a + 14d)| = |10d| = |10(-4)| = 40

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