Find the difference between the place values of 9 in the following number:
$99, 12, 61, 321$

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Solution

Find the place value of the respective digit and take their difference.
Place value of $9$ in $99, 12, 61, 321$ are $90, 00, 00, 000$ and $9, 00, 00, 000$
Difference $= 90, 00, 00, 000 - 9, 00, 00, 000$
$= 81, 00, 00, 000$
Thus, the required answer is $81, 00, 00, 000$ .

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