Find the difference between the quotient and remainder when $(x^{3} - 6 x^{2} + 11 x)$ is divided by $(x + 1)$ .

Open in App

Solution

$x + 1) x^{3} - 6 x^{2} + 11 x (x^{2} - 7 x + 18$
$\pm x^{3} \pm x^{2}$

$- 7 x^{2} + 11 x$
$\mp 7 x^{2} \mp 7 x$

$18 x$
$\pm 18 x \pm 18$

$- 18$

Quotient $= x^{2} - 7 x + 18$
Remainder $= - 18$
Quotient $-$ Remainder
$= x^{2} - 7 x + 36$ .

Suggest Corrections

Similar questions

Write the quotient and remainder when we divide.

$x^{3} - 6 x^{2} + 11 x - 6$ by $x^{2} - 5 x + 6$

x^{3} - 6 x^{2} + 11 x - 6

x + 2

P (x) = x^{3} + 4 x^{2} - 5 x + 6

g (x) = x + 1

f (x) = x^{3} - 6 x^{2} + 11 x - 6, g (x) = x + 2

p (x) = x^{3} - 6 x^{2} + 15 x - 8

g (x) = x - 2

Join BYJU'S Learning Program