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Byju's Answer
Standard X
Mathematics
Method of Finding LCM
Find the diff...
Question
Find the difference:
(i)
5
7
-
2
7
(ii)
5
6
-
3
4
(iii)
3
1
5
-
7
10
(iv)
7
-
4
2
3
(v)
3
3
10
-
1
7
15
(vi)
2
5
9
-
1
7
15
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Solution
(i)
5
7
-
2
7
=
5
-
2
7
=
3
7
(ii)
5
6
-
3
4
=
10
12
-
9
12
[∵ LCM of 6 and 4 = 12]
=
10
-
9
12
=
1
12
(iii)
3
1
5
-
7
10
=
16
5
-
7
10
=
32
10
-
7
10
[∵ LCM of 5 and 10 = 10]
=
32
-
7
10
=
25
10
=
5
2
=
2
1
2
(iv)
7
-
4
2
3
=
7
1
-
14
3
=
21
-
14
3
[∵ LCM of 1 and 3 = 3]
=
7
3
=
2
1
3
(v)
3
3
10
-
1
7
15
=
33
10
-
22
15
=
99
-
44
30
[∵ LCM of 10 and 15 = 30]
=
55
30
=
11
6
=
1
5
6
(vi)
2
5
9
-
1
7
15
=
23
9
-
22
15
=
115
-
66
45
[∵ LCM of 9 and 15 = 45]
=
49
45
=
1
4
45
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Similar questions
Q.
Using the rearrangement property find the sum:
(i)
4
3
+
3
5
+
-
2
3
+
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5
(ii)
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Q.
Simplify:
(i)
2
3
+
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4
+
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2
(ii)
5
8
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5
+
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4
(iii)
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(iv)
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+
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1
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(viii)
5
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+
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4
(ix)
7
18
+
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6
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1
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Q.
Multiply:
(i)
7
11
by
5
4
(ii)
5
7
by
-
3
4
(iii)
(
-
2
)
9
by
5
11
(iv)
-
3
17
by
-
5
-
4
Q.
Multiply:
(i)
7
11
by
5
4
(ii)
5
7
by
-
3
4
(iii)
-
2
9
by
5
11
(iv)
-
3
17
by
-
5
-
4
(v)
9
-
7
by
36
-
11
(vi)
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11
13
by
-
21
7
(vii)
-
3
5
by
-
4
7
(viii)
-
15
11
by
7
Q.
Find the difference:
(i)
6
7
-
9
11
(ii)
8
-
5
9
(iii)
9
-
5
2
3
(iv)
4
3
10
-
1
2
15
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