146

You visited us 146 times! Enjoying our articles? Unlock Full Access!

Ideal Gas Equation

Find the diff...

Question

Find the difference in the number of atoms if container A and container B contains same mass of benzene $(C_{6} H_{6})$ and acetylene $(C_{2} H_{2})$ respectively.

Open in App

Solution

Let the mass be $x$ g in container A & B.
Then, the number of atoms in container $A = \frac{x}{78} \times N_{A} \times 12$
& in container $B = \frac{x}{26} \times N_{A} \times 4$
Now, the difference is
$\frac{x}{78} \times N_{A} \times 12 - \frac{x}{26} \times N_{A} \times 4$
$N_{A} (\frac{12 x - 12 x}{78}) = 0$
Hence, the difference in the number of atoms is $0$ .

Suggest Corrections

Similar questions

(C_{6} H_{6})

(C_{6} H_{12} O_{6})

(C_{2} H_{2})

(H_{2} O_{2})

I

C_{2} H_{6}, C_{2} H_{4}

C_{2} H_{2}

I I

C - C

C - H

3 C_{2} H_{2} ⟶ C_{6} H_{6}

K

0.01

1

10

O_{2}

O_{3}

A

B

X

A

Y

2 X

B

Join BYJU'S Learning Program