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Question

Find the differential coefficient of the function x2 log x sin x with respect to x.

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Solution

We need to find the differential coefficient of the function x2logxsinx with respect to x.

Let y=x2logxsinx

We need to find dydx.

Consider y=x2logxsinx

dydx=ddx(x2)logxsinx+x2ddx(logxsinx)

=2x(logxsinx)+x2[sinxddx(logx)+logxddx(sinx)]

=2x(logxsinx)+x2[sinxx+logxcosx]

dydx=2x(logxsinx)+xsinx+x2logxcosx

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