Find the differentiation of $y = x (log x)^{2}$

2 log x + (log x)^{2}

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2 log x - (log x)^{2}

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log x + (log x)^{2}

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None of the above

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Solution

The correct option is A $2 log x + (log x)^{2}$
$y = x (log x)^{2}$

$\frac{d y}{d x} = 2 x log x \cdot \frac{1}{x} + (log x)^{2}$

$= 2 log x + (log x)^{2}$

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Similar questions

\int \frac{\sqrt{x^{2} + 1} [l o g (x^{2} + 1) - 2 l o g x]}{x^{4}} d x

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2 log (x + 1) - log (x^{2} - 1) = log 2,

x =

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